If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6b^2-12b+6=0
a = 6; b = -12; c = +6;
Δ = b2-4ac
Δ = -122-4·6·6
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$b=\frac{-b}{2a}=\frac{12}{12}=1$
| (5x+2)(x+0)=0 | | 6x+10=15x+1 | | 2y+24=2y-18 | | X+9×3×+3=5x+5 | | 5n^2+2n-10=0 | | ×+35=2x+10 | | (2x-4)^2=20 | | 10+6n=34 | | 4x-5(x+2)=2x+1 | | 28-w=-5 | | 16.95+.84x=195.03 | | -22+2k=-24 | | 21y+14=-49 | | r^2=-12r-22 | | d-3.4/7=2.8 | | 5(3x-2)-7=-x-33 | | 28x-18=38 | | f/6-3=-5 | | x(0.01x-0.02)=0 | | 4x-24=-64 | | 9=x-(-9) | | y-18/3=9 | | 24=-6-3x | | 4p^2-4p+3=0 | | X-5=4/3x | | 3x^²+5=30 | | 5/x-3/0.16-x=0 | | 8n(28-n)=7(n-4) | | 1400=10z^²+2 | | q2= 2.34 | | 21=b-8 | | 4x+3=22÷7 |